Math, asked by PranabRaj7, 1 year ago

Plzzz plzzzz solve this it's urgent...

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Answered by subhamn201
3

cosec A + cot A - 1 / cot A - cosec A + 1 

we know that,cosec ² A - cot ² A = 1 

substituting this in the numerator 

cosec A + cot A -(cosec ² A - cot ² A) / (cot A - cosec A + 1) 

x²-y²= (x+y)(x-y) 

cosec A + cot A - (cosec A + cot A) (cosec A - cot A) / (cot A - cosec A + 1) 

taking common 

(cosec A + cot A)(1-cosec A + cot A) / (cot A - cosec A + 1) 

cancelling like terms in numerator and denominator 

we are left with cosec A + cot A 

= 1/sin A + cos A/sin A 

= (1+cos A) / sin A


i hope this is help you

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