Question

plzzz slove it .. chptr is complex number​

Answer 1

Answer:

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Step-by-step explanation:

Solution :

w=1−izz−i

⇒|w|=|(1−iz)||(z−i)|

⇒|w|2=|(1−iz)|2|(z−i)|2

⇒|w|2=|(1−i(x+iy))|2|(x+iy)−i|2

⇒12=|(1+y)−ix|2|x+(y−1)i|2

⇒x2+(y−1)2=x2+(1+y)2

⇒y−1=1+y

⇒y=0

∴z=x+i(0)=x

⇒z=x

So, z lies on real axis.

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