plzzz sol this plane it in easily manner please
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Step-by-step explanation:
one vertex is at origin
OB = 2a units
vertex B is 2a units from origin
==> coordinates of B is ( 2a , 0)
draw an altitude from A to OB it will also be the median because OAB is an equilateral triangle
let it intersect OB at P
P is midpoint of OB
==> coordinates of P is (0 , a)
as OB is in x axis and AP is perpendicular to OB
AP is parallel to y axis
now in triangle APB is right angled at P , AB = 2a , PB = a
==> by pythogorous theorem AP = root(3)a
A is at at a distance of root(3) from P and is parallel to y axis
==> coordinates of A is (a , root(3)a)
here is your answer
O(0,0) ; B(2a , 0) ; A( a , root(3)a)
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xyz93939:
pls mark me as brainliest
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by applying distance formula we can get the answer
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