Plzzz solv it fast no 5
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x = (100)^a
y =(10000)^b
z=(10)^c
now,
log{ 10√y/x²z³}
=log[ 10√(10000)^b /{(100)^a}²{(10)^c}³ ]
=log[{ 10(10)^4b/2}/(10)^4a ×(10)^3c ]
=log{ (10)^(2b + 1)/(10)^(4a +3c)}
=log[ 10^(2b +1 -4a -3c)]
= 2b + 1 -4a -3c
y =(10000)^b
z=(10)^c
now,
log{ 10√y/x²z³}
=log[ 10√(10000)^b /{(100)^a}²{(10)^c}³ ]
=log[{ 10(10)^4b/2}/(10)^4a ×(10)^3c ]
=log{ (10)^(2b + 1)/(10)^(4a +3c)}
=log[ 10^(2b +1 -4a -3c)]
= 2b + 1 -4a -3c
hrik21:
thanks a lot
wht is ur mrks in maths ths yr
out of 100
reply
:-)
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2
i hope this will usful to u
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