plzzz solve b part.....request
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When lines are perpendicular then
product of line slope is equal to zero . Now,
3x-5y=7 line first
And it slope (say m1) = 5/3
4x+ay+9=0 line second
And it slope ( say m2) = - a/4
now apply rule then,
m1 × m2 = 0
5/3 ×-a/3 = 0
-5a/9 = 0
a= 0
product of line slope is equal to zero . Now,
3x-5y=7 line first
And it slope (say m1) = 5/3
4x+ay+9=0 line second
And it slope ( say m2) = - a/4
now apply rule then,
m1 × m2 = 0
5/3 ×-a/3 = 0
-5a/9 = 0
a= 0
Sanaya625:
Sorry it equal to one
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If two lines are perpendicular then
Product of their slopes = -1
Hence
(3/5) *(-4/a) = -1
-12/5a = -1
a = 12/5
Product of their slopes = -1
Hence
(3/5) *(-4/a) = -1
-12/5a = -1
a = 12/5
r u sure
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