Question

plzzz solve fast
thnx
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Answer 1

let

$\frac{4x - 3}{2x + 1 } = y$

so the equation reduces to,

$y - \frac{10}{y} = 3 \\ {y}^{2} - 10 = 3y \\ {y}^{2} - 3y - 10 = 0 \\ (y - 5)(y + 2) = 0 \\ y = 5 \\ \frac{4x - 3}{2x + 1} = 5 \\ 4x - 3 = 10x + 5 \\ 8 = 6x \\ x = \frac{4}{3} \\ y = - 2 \\ \frac{4x - 3}{2x + 1} = - 2 \\ 4x - 3 = - 4x - 2 \\ 8x = 1 \\ x = \frac{1}{8} \\ \\ \\ \red{ans \: x = \frac{1}{8} \: and \: \frac{4}{3} }$

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