Question

plzzz solve it also.....i will be thankful to you...

Answer 1

let the weights be x,y,z kgs x+y+z/3= 84____(1)
let the weight of man d be p then X+y+z+p/4=80___(2)
then a goes and e comes so,
e=weight of d +3 =p+3
p+(p+3)+y+z/4=78____(3)
x+y+z=84×3=252
from solving (1) and (2) p=320-252=68kgs
substitute the weight of p in (3)
so 68+68+3+y+z/4=78
139+y+z= 312
y+z= 173____(4)
by (1) eqn we have x+y+z=252
substitute (4) then,x+173 = 252
X= 252-173
=79kgs

hope it helps......