Question

plzzz solve it fast
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Answer 1

Answer:

the answer is option b)0

Step-by-step explanation:

We have

a/b+b/a = 1⟹a^2+ b^2 −ab /ab = 0

Now back to the right hand side

a^3+b°3=(a+b)(a^2−ab+b^2)

We can notice that we have

a^2+b^2−ab/ab=0⟹a^2+b^2−ab=0

Trivially a,b≠0 .

Thus we have

a^3+b^3=(a+b)(a^2−ab+b^2)=(a+b)=0

The result is

The result isa3+b3=0