plzzz solve it fast no. 31 in the following image through logarithm
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Given that,
P=log20......................1
Q=log25.....................2
Also given that,
2log(x+1)=2P-Q
By putting eq1 and eq2 in above equation we get,
2log(x+1)=2(log20)-log25
log(x+1)²=2{log5+log4}-log5²
log(x+1)²=2log5+2log4-2log5
log(x+1)²=log2⁴
Removing log from both sides we get,
(x+1)²=2⁴
x+1=2²
x+1=4
x=3
Hence value of x=3.
P=log20......................1
Q=log25.....................2
Also given that,
2log(x+1)=2P-Q
By putting eq1 and eq2 in above equation we get,
2log(x+1)=2(log20)-log25
log(x+1)²=2{log5+log4}-log5²
log(x+1)²=2log5+2log4-2log5
log(x+1)²=log2⁴
Removing log from both sides we get,
(x+1)²=2⁴
x+1=2²
x+1=4
x=3
Hence value of x=3.
hrik21:
plzz explain ur 11th line
can u write that line please
is that removing of log?
for finding any variable we can remove log from both sides such that if value of that variable is substituted the equation get satisfied
but we need to make single quantities on both sides
Answered by
2
by using properties of logarithm we can solve this problem...
see attachment. .
here x = 3 is the solution
but x = -5 is not the solution of given equation... because argument of log never be negative..
___________________________
hope it will help u
see attachment. .
here x = 3 is the solution
but x = -5 is not the solution of given equation... because argument of log never be negative..
___________________________
hope it will help u
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ur process is talf
i given complete solution....
ok ok it's easy
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