Question

plzzz solve it....from kinematics

Answer 1

Relative velocity of Q wrt P = (-2i + j),

Relative position of Q wrt P = (2i + j).

Path of Q in frame of P will touch (0,2) point and (2,1) point

So Q will move along a line 2y+x=4 wrt P.

Shortest distance between P and Q = 4/rt(4+1) = 4/rt(5).........

which is perpendicular distance between (0,0)

and

2y+x=4.

HOPE IT HELP

☣Aman☣

Answer 2

option (b) is right......✔✔✔