Question

plzzz solve ot fast ​

Answer 1

Given,

$8^{x+1} +(4^x)^{3/2} = 18\\(2^3)^{x+1} + ((2^2)^x)^{3/2} = 18\\2^{3x+3}+2^{3x} = 18\\2^{3x}.2^3 + 2^{3x} = 18\\2^{3x}(8 + 1) = 18\\9.2^{3x} = 18\\2^{3x} = 2^1\\3x = 1\\x = 1/3$