Question

Plzzz solve question no 2 plzzzzz​

Answer 1

Answer:

x=7

Step-by-step explanation:

(2x) cube+(3x)cube+(4x)cube=33957

8xcube+ 27xcube+ 64 x cube= 33957

99xcube=33957

x cube= 33957/99

x cube=343

x= cube root 343

x=7

Answer 2

Question :-

Three numbers are in the ratio 2 : 3 : 4. The sum of their cubes is 33957. Find the numbeers.

Answer :-

The numbers are 14, 21 and 28 respectively.

Explanation :-

Given :

• Ratio of two numbers - 2 : 3 : 4
• The sum of their cubes - 33957

To find :

The three numbers which are in the ratio 2 : 3 : 4

Solution :

Let the first number be 2x

the second number be 3x

and the third number be 4x

According to question,

$= > {(2x)}^{3} + {(3x)}^{3} + {(4x)}^{3} = 33957$

$= > {8x}^{3} + {27x}^{3} + {64x}^{3} = 33957$

$= > {99x}^{3} = 33957$

$= > {x}^{3} = \dfrac{33957}{99}$

$= > {x}^{3} = 343$

$= > x = \sqrt[3]{343}$

$= > x = 7$

Hence, the value of x is 7.

Now, the first number => 7 × 2 = 14

The second number => 7 × 3 = 21

and the third number => 7 × 4 = 28