Question

Plzzz.... Solve the 1st question ,,,,,It's very urgent

Answer 1

Answer:-

$7 \sqrt{ \frac{1}{3} } - 2 \frac{1}{3} \sqrt{ \frac{1}{3} } + 3 \sqrt{147}$

$=> 7 \frac{1}{ \sqrt{3} } - 2 \frac{1}{3} \frac{1}{ \sqrt{3} } + 3 \times 7 \sqrt{3}$

$=>\frac{7}{\sqrt{3}}-\frac{2}{3} \frac{1}{\sqrt{3}}+21\times \sqrt{3}\times\frac{\sqrt{3}}{ \sqrt{3}}$

$=> \frac{1}{ \sqrt{3} } (7 - \frac{2}{3} + 21 \times 3)$

$=> \frac{1}{ \sqrt{3} } ( \frac{21 - 2}{3} + 63)$

$=> \frac{1}{ \sqrt{3} } ( \frac{19 + 63 \times 3}{3})$

$=> \frac{1}{ \sqrt{3} } ( \frac{19 + 189}{3})$

$=> \frac{1}{ \sqrt{3} } ( \frac{208}{3})$

$=> \frac{1}{ \sqrt{3} } (66)$

$=> \frac{66}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} }$

$=> \frac{66 \sqrt{3} }{3}$

$=> 33 \sqrt{3}$

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Answer 2

thank you for such a question