Physics, asked by bala8335, 4 months ago

Plzzz solve the problem....... ​

Attachments:

Answers

Answered by BrainlyEmpire
26

Answer:-

  • The aeroplane would have covered 1440 m on the runway.

Given :-

  • An aeroplane taxies on the runway for 30 s with an acceleration of 3.2 m/s² before taking off.

To find :-

  • How much distance would it have covered on the runway ?

Solution :-

Formula used :——

  • {\boxed{\sf{S=ut+\dfrac{1}{2}at^2}}}

  • t = time = 30 s
  • a = acceleration = 3.2 m/s²
  • u = initial velocity = 0 m/s

[put values]

\mapsto\sf{S=0\times\:t+\dfrac{1}{2}\times\:3.2\times\:(30)^2}

\mapsto\sf{S=0+(16\times\:3\times\:30)}

\mapsto\sf{S=1440}

  • Therefore, it would have covered 1440 m on the runway.

____________________

Some formulas :—

  • \sf{v=u+at}
  • \sf{v^2=u^2+2as}
  • \sf{s_n=u+\dfrac{1}{2}a(2n-1)}
Answered by hanshikasharma28
0

Please mark as brainliest

please follow me

Attachments:
Similar questions