Question

plzzz solve the problem as soon as possible​

Answer 1

Answer:

x = 4

Step-by-step explanation:

$\displaystyle\quad\ 6^{2x+4} = 3^{3x}\cdot 2^{x+8}\\\\\Rightarrow 3^{2x+4}\cdot 2^{2x+4} = 3^{3x}\cdot 2^{x+8}\\\\\Rightarrow 2^{(2x+4)-(x+8)}=3^{3x-(2x+4)}\\\\\Rightarrow 2^{x-4} = 3^{x-4} \\\\\Rightarrow \left(\tfrac23\right)^{x-4}=1\\\\\Rightarrow x-4 = 0\\\\\Rightarrow x = 4$