PLZZZ SOLVE THE PROBLEM NO. c GVN BELOW.....
TOMORROW IS MY EXAM
Attachments:
Answers
Answered by
2
LET THE JOINING POINT OF EG AND DF BE O.
∠GBE=∠FDC(CORRESPONDING)
BD=EC⇒BD+DE=EC+DE⇒BE=DC
∠BGE=∠DOE(CORRESPONDING)
∠CFD=∠DOE(CORRESPONDING ANGLE)
SO ΔBGE≡ΔDFC
∠GBE=∠FDC(CORRESPONDING)
BD=EC⇒BD+DE=EC+DE⇒BE=DC
∠BGE=∠DOE(CORRESPONDING)
∠CFD=∠DOE(CORRESPONDING ANGLE)
SO ΔBGE≡ΔDFC
Similar questions