Question

Plzzz solve the problem with explanation​

Answer 1

Given:-

• The sum of three consecutive integers is 5 more than the smallest of the integers.

To Find:-

• Three Consecutive Integers = ?

Solution : -

$\longrightarrow$ Suppose the three consecutive integers are :-

The First Consecutive integer be a

The Second Consecutive integer be a + 1

The Third Consecutive integer be a + 2

According to the Question :-

$\mapsto \sf{a+a+1+a+2 = a + 5}$

$\mapsto \sf{3a + 3 = a + 5}$

$\mapsto \sf{3a - a = 5-3}$

$\mapsto \sf{2a = 2}$

$\mapsto \sf{a = \dfrac{2}{2}}$

$\mapsto \boxed{\red{\sf{a = 1}}}$

Therefore,

The First Consecutive integer be a = 1

The Second Consecutive integer be a + 1 = 2

The Third Consecutive integer be a + 2 = 3

$\rule{200}2$

Answer 2

Step-by-step explanation:

let three interger x , x+1 , x+2

sum = x+x+1+x+2

= 3x +3

then 3x +3 = 5+x

or 2x =2

or x= 1

integers are 1 ,2 and 3