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A refer to first term
N refers to position of term that want
D is common difference
Tn = term u want
Example :
1,2,3,4,5,6
Here a=1
D= 2-1
=1
If u want 4th term then:
N=4
Tn=4
Therfore
4 = 1 + (4-1)1
4=1+3
4=4
{---->Or<----}
Arithmetic Progression, AP
Definition
Arithmetic Progression (also called arithmetic sequence), is a sequence of numbers such that the difference between any two consecutive terms is constant. Each term therefore in an arithmetic progression will increase or decrease at a constant value called the common difference, d.
Examples of arithmetic progression are:
2, 5, 8, 11,... common difference = 3
23, 19, 15, 11,... common difference = -4
Derivation of Formulas
Let
dd = common difference
a1a1 = first term
a2a2 = second term
a3a3 = third term
amam = mth term or any term before anan
anan = nth term or last term
d=a2−a1=a3−a2=a4−a3d=a2−a1=a3−a2=a4−a3 and so on.
Derivation for an in terms of a1 and d
a1=a1a1=a1
a2=a1+da2=a1+d
a3=a2+d=(a1+d)+d=a1+2da3=a2+d=(a1+d)+d=a1+2d
a4=a3+d=(a1+2d)+d=a1+3da4=a3+d=(a1+2d)+d=a1+3d
a5=a4+d=(a1+3d)+d=a1+4da5=a4+d=(a1+3d)+d=a1+4d
...
am=a1+(m−1)dam=a1+(m−1)d
...
an=a1+(n−1)d
N refers to position of term that want
D is common difference
Tn = term u want
Example :
1,2,3,4,5,6
Here a=1
D= 2-1
=1
If u want 4th term then:
N=4
Tn=4
Therfore
4 = 1 + (4-1)1
4=1+3
4=4
{---->Or<----}
Arithmetic Progression, AP
Definition
Arithmetic Progression (also called arithmetic sequence), is a sequence of numbers such that the difference between any two consecutive terms is constant. Each term therefore in an arithmetic progression will increase or decrease at a constant value called the common difference, d.
Examples of arithmetic progression are:
2, 5, 8, 11,... common difference = 3
23, 19, 15, 11,... common difference = -4
Derivation of Formulas
Let
dd = common difference
a1a1 = first term
a2a2 = second term
a3a3 = third term
amam = mth term or any term before anan
anan = nth term or last term
d=a2−a1=a3−a2=a4−a3d=a2−a1=a3−a2=a4−a3 and so on.
Derivation for an in terms of a1 and d
a1=a1a1=a1
a2=a1+da2=a1+d
a3=a2+d=(a1+d)+d=a1+2da3=a2+d=(a1+d)+d=a1+2d
a4=a3+d=(a1+2d)+d=a1+3da4=a3+d=(a1+2d)+d=a1+3d
a5=a4+d=(a1+3d)+d=a1+4da5=a4+d=(a1+3d)+d=a1+4d
...
am=a1+(m−1)dam=a1+(m−1)d
...
an=a1+(n−1)d
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