Question

plzzz solve the question


factorise the math statement


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Answer 1

Answer:

(1+2a)² - 8a

1 + 4a² + 4a - 8a

4a² - 4a + 1

4a² - 2a - 2a + 1

2a(2a-1)-1(2a-1)

(2a-1)(2a-1)

Factors are -

2a - 1 = 0

a = 1/2

Answer 2

$\huge{\boxed{\boxed{\red{\ulcorner{\mid{\overline{\underline{\bf{Answer:-}}}}}\mid}}}}$

${(1 + 2a)}^{2} - 8a . \\ \\ {1}^{2} + 4 {a}^{2} + 2a - 8a. \\ \\ 4 {a}^{2} - 6a + 1. \\ \\ \\where \: \\ \\ a = 4 \: \: \: \: \: b = - 6 \: \: \: \: \: c = 1 \\ \\ \\ a = \frac{ - b ±\sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ = \frac{6 ± \sqrt{ {( - 6)}^{2} - 4 \times 4 \times 1} }{8} . \\ \\ = \frac{6± \sqrt{36 - 16} }{8} \\ \\ = \frac{6 ± \sqrt{20} }{8} \\ \\ = \frac{6 ± 2\sqrt{5} }{8} \\ \\ = \cancel\frac{2(3± \sqrt{5} )}{8} \\ \\ = \frac{3 ± \sqrt{5} }{4} . \\ \\ \\ \\ or \\ \\ \\ \\ a = \frac{3 + \sqrt{5} }{4} \: \: \: \: \: and \: \: \: \: a = \frac{3 - \sqrt{5} }{4} .$

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