Question

plzzz solve the questions hurry up​

Answer 1

Answer:

Let ABCD be a cyclic quadrilateral whose diagonals AC and BD intersect at O at right angles . Let

such that LO produced meets CD at M. <br> Then, we have to prove that CM

MD <br> Clearly,

in the same segment] <br>

<br>

LOM is a straight line and

<br> Thus,

and

<br>

OM

CM and similarly,

. <br> Hence

Answer 2

ques no. 25

given: two right triangle ABC and triangle ADB having common hypotenuse

to prove : angle BAC is equal to angle bdc proof : because Triangle ACB and ADB are right Triangles and having common hypotenuse

they are Triangles in semicircle and point a b c and d are are concyclic angle BAC is equal to BDC angles by same arc in segment of circle .......

hope it will hlp u although you don't need but may be