Question

plzzz solve this..... ​

Answer 1

SOLUTION:-

Given:

$\frac{ {sin}^{2}63 \degree + {sin}^{2} 27 \degree }{ {cos}^{2}17 \degree + {cos}^{2}73 \degree }$

Therefore,

$= > \frac{ {sin}^{2}(90 - 27) + {sin}^{2} 27 \degree }{ {cos}^{2}17 \degree(90 - 73) + {cos}^{2}73 \degree } \\ \\ = > \frac{ {cos}^{2}27 \degree + {sin}^{2} 27 \degree }{ {sin}^{2}73 \degree + {cos}^{2} 73 \degree} \\ \\ = > \frac{1}{1} \: \: \: \: \: \: [ {cos}^{2} A + sin {}^{2} A = 1]\\ \\ = > 1$

Hope it helps ☺️