Question

plzzz solve this......

Answer 1

Heyy Dear ❤
Here is u r Ans ➡

IV) Two blocks are connected over a pulley as shown in the Figure below. The mass of block A is 10 kg and the coefficient of kinetic friction is 0.20. The angle  is 300. Block A slides down the incline at constant speed. What is the mass of block B?





Solution: 
We know that if we sum the forces on block A in the plane of the incline, we get 
T - Ff - W 
Where the force of friction is given by 
F f = ukN (mAg cos θ )

and the component of the weight in the direction of the incline is given by 

W = mAg sin θ

Solving for the tension, T, we find 
T = mAg (sin 30° - uk cos 30° )

and we know that 
T - mBg = 0 
so we find that 
mB = mA (sin 30° - uk cos 30° )
or 
mB  =  3.3 kg 
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Hope This Helps u ☺.

Answer 2

Hey mate.....

here's ur answer....

W = mag sin (theta)

t = mag (sine (theta) - cos (theta))

T - mbg = 0

mb = ma ( sin30° - cos30°)

$<marquee>mb = 3.3</marquee>$

Hope it helps❤❤❤