plzzz solve this !!!!
Attachments:
Answers
Answered by
0
(secA sinC-tanA.tanC)/sinB
={(AC/AB)×(AB/AC)-(BC/AB)×(AB/BC)}/sin90°
=(1-1)/1
=0/1
=0
={(AC/AB)×(AB/AC)-(BC/AB)×(AB/BC)}/sin90°
=(1-1)/1
=0/1
=0
Answered by
0
NYC question ans is zero
Similar questions