Math, asked by aqawi317, 9 months ago

plzzz solve this fast
if u correctly solve I will mark u as brainliest.....​

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Answers

Answered by sathish24499k
1

LHS=CosA/(1-sinA/cosA) +sin2A/sinA-cosA)

=cos2A/(cosA-sinA) +sin2A/(sinA-cosA)

=-cos2A/(sinA-cosA)+sin2A/(sinA-cosA)

=(sin2A-cos2A)/(sinA-CosA)

(a2-b2)=(a+b)(a-b)

=(sinA+cosA)(sinA-cosA)/(sinA-cosA)

=sinA+cosA

LHS=RHS

Hence proved

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