plzzz solve this fast
if u correctly solve I will mark u as brainliest.....
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LHS=CosA/(1-sinA/cosA) +sin2A/sinA-cosA)
=cos2A/(cosA-sinA) +sin2A/(sinA-cosA)
=-cos2A/(sinA-cosA)+sin2A/(sinA-cosA)
=(sin2A-cos2A)/(sinA-CosA)
(a2-b2)=(a+b)(a-b)
=(sinA+cosA)(sinA-cosA)/(sinA-cosA)
=sinA+cosA
LHS=RHS
Hence proved
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