Plzzz solve this problem..
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area of triangle OAB= 1/2. 4.AB
AREA OF OAC= 1/2. 6 . AC
AREA OF OBC= 1/2 . 10 .BC
AB= BC = AC
AREA OAB= 2AB
AREA OAC= 3AB
AREA OBC= 5AB
TOTAL AREA= 10 AB
AS EQUILATERAL TRIANGLE AREA IS √3/4 . AB^2
= 10 AB = √3/4 . AB^2
40/√3= AB
AREA OF OAC= 1/2. 6 . AC
AREA OF OBC= 1/2 . 10 .BC
AB= BC = AC
AREA OAB= 2AB
AREA OAC= 3AB
AREA OBC= 5AB
TOTAL AREA= 10 AB
AS EQUILATERAL TRIANGLE AREA IS √3/4 . AB^2
= 10 AB = √3/4 . AB^2
40/√3= AB
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