Math, asked by Anonymous, 1 year ago

plzzz solve this q fast..I have my xam

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Anonymous: somebody plzzz solve...
dkumar701: don't worry
dkumar701: stud well for your exam
Anonymous: thanks..
dkumar701: welcome

Answers

Answered by dkumar701
1
x2=1 then x=root of 1
then x=1
sub x in the value
x4+x2+8x2+ax+b=1+1+8+a+b
10+a+b=0------->1
b=-10-a--------->2
sub equation 2 in 1
10+a-10-a=0
a=0------>3
sub a in equation 1
10+0+b=0
b=-10
so, a=0;b=-10

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