plzzz solve this q fast..I have my xam
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Steph0303:
question is not clear
Gfch
find the condition that the zeros of p(x) =x3-px2+qx-r may b a-d,a,a+d
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sum of the roots = p..... a-d+a+a+d = p...... 3a = p ....... a = p/3
a is a root , therefore a can be plugged in place of x
[p/3]^3 - p[p/3]^2 + q[p/3] - r = 0
simplify this
2p^3 - 9pq + 27r = 0 is the condition
a is a root , therefore a can be plugged in place of x
[p/3]^3 - p[p/3]^2 + q[p/3] - r = 0
simplify this
2p^3 - 9pq + 27r = 0 is the condition
hope it helps
yp...thnxs
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