Question

plzzz solve this question.​

Answer 1

$\huge\text{\underline{Answer}}$

$\sf{\underline{Given }}$

$\bold{ 3∠ A = 4∠B = 6∠C}$

$\bold{∠A = \frac{4∠b}{3} }$

$\bold{∠C = \frac{4∠B}{6}}$

Now, sum of angle of a triangle = 180°

$\implies$ $\bold{∠A +∠ B + ∠C = 180°}$

Putting the value of ∠ A and ∠C

$\implies$ $\bold{ \frac{4∠B}{3} + ∠B + \frac{4∠B}{6} = 180°}$

$\implies$ $\bold{\frac{8∠B + 6∠B + 4∠B}{6} = 180 }$

$\implies$ $\bold{ 18∠B = 1080}$

$\implies$ $\bold{∠B = 60° }$

Putting the value of ∠B

$\implies$ $\bold{∠A = 80° }$

$\implies$ $\bold{∠C = 40° }$

$\huge\text{\underline{Verification}}$

$\bold{∠A +∠ B + ∠C = 180°}$

$\bold{60° + 80° + 40° = 180° }$

$\bold{180° = 180° }$

hence verified....