plzzz solve this question fast....
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serdan2114:
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x^2(a+b)+2(b+c)+2(c+a) _____________________
x^4a+4b+4c
[base are same]
=x^2a+2b+2b+2c+2c+2a-(4a+4b+4c). [ base are same]
=x^4a+4b+4c-4a-4b-4c
=x^0
=1
here,it is proved.
x^4a+4b+4c
[base are same]
=x^2a+2b+2b+2c+2c+2a-(4a+4b+4c). [ base are same]
=x^4a+4b+4c-4a-4b-4c
=x^0
=1
here,it is proved.
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