plzzz. solve this question. ...with explanation ........plz it's urgent. .....
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Answer:
( d ).
Step-by-step explanation:
Given,
l 3 - 4x l ≥ 9
Case 1 :
= > + ( 3 - 4x ) ≥ 9
= > 3 - 4x ≥ 9
= > 3 - 9 ≥ 4x
= > - 6 ≥ 4x
= > - 6 / 4 ≥ x
= > - 3 / 2 ≥ x
This says : x € ( - ∞ , - 3 / 2 ] { any negative value greater than - 3 / 2, including - 3 / 2 }
Case 2 :
= > - ( 3 - 4x ) ≥ 9
= > 4x - 3 ≥ 9
= > 4x ≥ 9 + 3
= > 4x ≥ 12
= > x ≥ 12 / 4
= > x ≥ 3
This says : x € [ 3 , ∞ ) { x is greater than 3 or 3 }
From both the cases, x € ( - ∞ , - 3 / 2 ] U [ 3 , ∞ ).
Thus, option ( d ) is the correct option.
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