Plzzz solve this quickly for 20 points
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28. LCM of a^2/bc+b^2/ca+c^2/ab is
(a^3+b^3+c^3)/abc
we know that
a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)
a+b+c=0
a^3+b^3+c^3-3abc=0
a^3+b^3+c^3=3abc
so
3abc/abc=3
29.
ab+bc+CX+ax= a(b+x)+c(b+x)
(b+x)(a+c)
(a^3+b^3+c^3)/abc
we know that
a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)
a+b+c=0
a^3+b^3+c^3-3abc=0
a^3+b^3+c^3=3abc
so
3abc/abc=3
29.
ab+bc+CX+ax= a(b+x)+c(b+x)
(b+x)(a+c)
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