Question

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Answer 1

Answer:

Hello!!

Step-by-step explanation:

i) In triangle ADC

S and R are the mid points of sidesAD and CD respectively.

So, by mid point theorem

SR II AC and SR = 1/2AC

ii) In triangle BAC

P and Q are mid points of sides BA and BC respectively

So, by mid point theorem

PQ II AC and PQ = 1/2AC

Since PQ and SR are both parallel to AC

Therefore PQ = SR and alsoPQ II SR

iii) Since, we has proved that PQ II SR

Therefore, PQRS is a parallelogram.

HENCE PROVED

PLEASE MARK IT BRAINILIEST

Answer 2

In ABC, P is the mid-point of AB and Q is the mid-point of BC.

Then PQ AC and PQ = AC

(i) In ACD, R is the mid-point of CD and S is the mid-point of AD.

Then SR AC and SR = AC

(ii) Since PQ = AC and SR = AC

Therefore, PQ = SR

(iii) Since PQ AC and SR AC

Therefore, PQ SR [two lines parallel to given line are parallel to each other]

Now PQ = SR and PQ SR

Therefore, PQRS is a parallelogram.

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