plzzz solved 6.
tomorrow my exam
Attachments:
Answers
Answered by
0
angle C = angle A = 75°
( opposite side of parallelogram are equal)
In triangle BDC
angle DBC + angle DCA + angle CDB=180°
60°+75°+angle CDB = 180°
angle CDB = 180°-135° = 45°
( opposite side of parallelogram are equal)
In triangle BDC
angle DBC + angle DCA + angle CDB=180°
60°+75°+angle CDB = 180°
angle CDB = 180°-135° = 45°
Similar questions