Math, asked by yadavanshikadec2007, 10 months ago

plzzz someone answer it​

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Answered by spsnehasourabh6
1

Step-by-step explanation:

 {9}^{ \frac{3}{2} }  + 3 \times  {4}^{0}  -   { \frac{1}{81} }^{ \frac{ - 1}{2} }

9 is written as 3 square and 4 power 0 is equal to 1

and to remove the minus of power 1/2

the base is reciprocaled

 { {3}^{2 \times  \frac{3}{2} } }^{}  + 3 \times 1 -  { \frac{81}{1} }^{ \frac{1}{2} }

cancel the 2s at the power of base 3

 {3}^{3}  + 3 -   {9}^{2 \times  \frac{1}{2} }

27 + 3 - 9

 = 21

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