Question

plzzz someone answer it​

Answer 1

Step-by-step explanation:

${9}^{ \frac{3}{2} } + 3 \times {4}^{0} - { \frac{1}{81} }^{ \frac{ - 1}{2} }$

9 is written as 3 square and 4 power 0 is equal to 1

and to remove the minus of power 1/2

the base is reciprocaled

${ {3}^{2 \times \frac{3}{2} } }^{} + 3 \times 1 - { \frac{81}{1} }^{ \frac{1}{2} }$

cancel the 2s at the power of base 3

${3}^{3} + 3 - {9}^{2 \times \frac{1}{2} }$

$27 + 3 - 9$

$= 21$