Question

plzzz tell me the solution
$\frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} }$
RATIONLIZE THE DENOMINATOR

Answer 1

Multiple and divide with 3-2√2

(3-2√2)^2/(3+2√2)(3-2√2)
(9+8-12√2)/(9-8)
(17-12√2)/1

Answer 2

heya!!! here's ur answer...
$= \frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2 } } \times \frac{3 - 2 \sqrt{2} }{3 - 2 \sqrt{2} } \\ = \frac{ {(3 - 2 \sqrt{2)} }^{2} }{ {3}^{2} - {(2 \sqrt{2)} }^{2} } \\ = \frac{ {3}^{2} + ( {2 \sqrt{2)} }^{2} - 2 \times 3 \times 2 \sqrt{2} }{9 - 8} \\ = \frac{9 + 8 - 12 \sqrt{2} }{1} \\ = 17 - 12 \sqrt{2}$

Hope it helps u... :-)