Question

plzzz tell the answer

Answer 1

x³ - 1/x³  - 14 = 0

a = x³

a - 1/a - 14 = 0

a² - 14a - 1  =0

Apply quadratic equation

 -b +/-  √b² - 4ac  

        2a

=     14 +/-  √ 196 + 4  

                  2

= 14 +/-  √200    =    7 +/-  5√2

            2

[ a - (7+5√2)]  [a - (7-5√2)]

[ x³ - (7+5√2)]  [x³ - (7-5√2)]