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in triangle ABC
angle A +angleB+angle C=180
angle A+65+33=180
angle A=180-98=82 ;
it is given that AN is the bisector of angle A
angle NAC=82/2=41;
in triangle NAC
angleANC=180-(angleNAC+angle CAN)
angle ANC=180-74=106 ;
again angle ANC=angle NMA+angleMAN
106=90+MAN
angle MAN=16
so., angle MAN=16°
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