.plzzzx ans...logarithms.....thnk u
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Hey there !!
Using the condition
logab=loga+logb and logaˣ=xloga
logV+log3=logπ+log4+3logr--------------------equation 1
3logr =logr³ ,logV+log3=log3V
So using these equation 1 changes to
log3V=log4πr³
3V=4πr³
V=4πr³/3
Hope this helped you !!!!!
Using the condition
logab=loga+logb and logaˣ=xloga
logV+log3=logπ+log4+3logr--------------------equation 1
3logr =logr³ ,logV+log3=log3V
So using these equation 1 changes to
log3V=log4πr³
3V=4πr³
V=4πr³/3
Hope this helped you !!!!!
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