Math, asked by sanj2, 1 year ago

plzzzz ans...Indices....Thank you

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Answers

Answered by vaibhav789
1
 m-n-1/(m^2+mn+n^2)
=[m(m^2+mn+n^2)-n(m^2+mn+n^2)-1]/(m^2+mn+n^2)
=m^3+m^2n+mn^2-m^2n-mn^2-n^3-1/(m^2+mn+n^2)
=m^3-n^3-1/(m^2+mn+n^2)
=(cube-root 15)^3-(cube-root 14)^3-1/(m^2+mn+n^2)
=15-14-1/(m^2+mn+n^2)
=1-1/(m^2+mn+n^2)
=0/(m^2+mn+n^2)
=0
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