Question

Plzzzz answer 8th question as soon as possible.

Answer 1

Step-by-step explanation:

$a = \frac{1}{4 - a} \\ \frac{1}{a} = 4 - a \\ \frac{1}{a} + a = 4 \\ a {}^{2} + \frac{1}{a {}^{2} } = (a + \frac{1}{a} ) {}^{2} - 2 \\ 4 {}^{2} - 2 \\ 16 - 2 \\ 14 \\ therefore \\ a {}^{3} + \frac{1}{a {}^{3} } = (a + \frac{1}{a}) (a {}^{2} + \frac{1}{a {}^{2} } - 1) \\ 4 \times (14 - 1) \\ 4 \times 13 \\ 52$

Answer 2

Answer:

a+1/a

given =a=1/4-a

a^2-4a+1

a=2+root3, 2-root3

a+1/a=2+root3+2-root3

4