Question

Plzzzz Answer faaaast ................

Answer 1

Answer:

8.8 cm

Step-by-step explanation:

Area of ΔABC = 121 cm²,  ΔDEF = 64 cm² and median of ΔABC = 12.1 cm.

Let the median of the Δ DEF be 'x' cm.

∴ Area of two similar triangles is = ratio of squares of their corresponding sides.

⇒ (121/64) = (12.1)²/x²

⇒ 121 * x² = (12.1)² * 64

⇒ 121 * x² = 146.41 * 64

⇒ 121 * x² = 9370.24

⇒ x² = 77.44 cm

⇒ x = 8.8 cm.

Therefore, Median of ΔDEF = 8.8 cm.

Hope it helps!

Answer 2

$\bf{\boxed{\boxed {\huge{Step \:by\:step\:explanation}}}}$

$<b ><u>Answer</b></u>$

area of triangle ABC =121cm², triangle DEF = 64 cm ² and median of triangle ABC =12.1cm

let,
the median of triangle DEF='X'

area of two similar triangles is =ratio of a square of their corresponding sides .

=(121/64) = (12.1)² ÷x²

=121 × x² = (12.1)² ×64

=121 × x² = 9370.24

=x² = 77.44 cm

=x = 8.8cm

$\bf{\boxed{\boxed{\huge{\therefore\:the\:median\:of\:triangle\:DEF\:is\:8.8cm}}}}$

${\thanks}$