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Answers
A) 4 times of the original pressure
B) 3 times of the original pressure
C)3/2 times of the original pressure
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According to Boyle's law : P₁V₁ = P₂V₂
(a) Initial Pressure : P₁ and Initial Volume : V₁
Given that Final Volume is 1/4th of the Initial Volume
⇒ V₂ = 1/4 × V₁
Substituting in Boyle's law we get :
⇒ P₁ × V₁ = P₂ × 1/4 × V₁
⇒ P₂ = 4P₁
Hence the Pressure applied must be 4 times the Original Pressure
(b) Initial Pressure : P₁ and Initial Volume : V₁
Given that Final Volume is 1/3rd of the Initial Volume
⇒ V₂ = 1/3 × V₁
Substituting in Boyle's law we get :
⇒ P₁ × V₁ = P₂ × 1/3 × V₁
⇒ P₂ = 3P₁
Hence the Pressure applied must be 3 times the Original Pressure
(c) Initial Pressure : P₁ and Initial Volume : V₁
Given that Final Volume is 2/3rd of the Initial Volume
⇒ V₂ = 2/3 × V₁
Substituting in Boyle's law we get :
⇒ P₁ × V₁ = P₂ × 2/3 × V₁
⇒ P₂ = 3/2 × P₁
Hence the Pressure applied must be 3/2 times the Original Pressure