Question

plzzzz bata do koi. help help​

Answer 1

Question :

${( \frac{a}{b}) }^{4} \times { (\frac{4ab}{3a}) }^{2} \times { (\frac{b}{2a} )}^{3}$

$\huge\purple{Required \: Answer :}$

$= \frac{ {a}^{4} }{ {b}^{4} } \times \frac{ {16a}^{2}{b}^{2} }{9 {a}^{2} } \times \frac{ {b}^{3} }{8 {a}^{3} } \\ = \frac{ {a}^{4} \times 16 {a}^{2} {b}^{2} \times {b}^{3} }{ {b}^{4} \times 9 {a}^{2} \times 8 {a}^{3} } \\ = \frac{16 {a}^{4 + 2} {b}^{2 + 3} }{72 {a}^{2 + 3} {b}^{4} } \\ = \frac{16 {a}^{6} {b}^{5} }{72 {a}^{5} {b}^{4} } \\ = \frac{16ab}{72} \\72 = 16ab \\ ab = \frac{72}{16} \\ ab = 4.5$

Answer 2

Step-by-step explanation:

a^4/b^4×16a^2b^2/9a^2×b^3/4a ^3

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