Math, asked by janhavishelke15, 8 months ago

plzzzz batao yrr dimag ke upar ja raha hai
ye linear inequality ne to jindagi haram kar di yarr
kal test hai mera plzz help me!!!​

Attachments:

Answers

Answered by ShuchiRecites
72

Solution: The question is easy to solve so let's first solve Right Hand side.

→ (3x - 2)/4 - (5x - 3)/5

Step 1 - Take L.C.M which is 20

→ [5(3x - 2) - 4(5x - 3)]/20

→ [15x - 10 - 20x + 12]/20

→ (2 - 5x)/20

Step 2 - Let's equate it now

→ x/5 < (2 - 5x)/20

→ 20x/5 < (2 - 5x) [i just shifted 20 to another side]

→ 4x < 2 - 5x

→ 9x < 2 → x < 2/9

Okay, so x is smaller than 2/9 but how much it is greater to other values isn't defined. (Hinglish mein bole toh, woh 2/9 se bada hai, par kitno se chhota hai woh defined nahi)

Hence, x belongs to (- ∞, 2/9)

(Hinglish: Ek prakar se - ∞ < x < 2/9)

Note: Remember, for < and > we use ( ) brackets & for ≤ and ≥ we use [ ] brackets.

God Bless :)

Answered by Yashicaruthvik
3

Answer:

x/5 < (2 - 5x)/20

→ 20x/5 < (2 - 5x) [i just shifted 20 to another side]

→ 4x < 2 - 5x

→ 9x < 2 → x < 2/9

Okay, so x is smaller than 2/9 but how much it is greater to other values isn't defined

Step-by-step explanation:

Similar questions