plzzzz batao yrr dimag ke upar ja raha hai
ye linear inequality ne to jindagi haram kar di yarr
kal test hai mera plzz help me!!!
Answers
Solution: The question is easy to solve so let's first solve Right Hand side.
→ (3x - 2)/4 - (5x - 3)/5
Step 1 - Take L.C.M which is 20
→ [5(3x - 2) - 4(5x - 3)]/20
→ [15x - 10 - 20x + 12]/20
→ (2 - 5x)/20
Step 2 - Let's equate it now
→ x/5 < (2 - 5x)/20
→ 20x/5 < (2 - 5x) [i just shifted 20 to another side]
→ 4x < 2 - 5x
→ 9x < 2 → x < 2/9
Okay, so x is smaller than 2/9 but how much it is greater to other values isn't defined. (Hinglish mein bole toh, woh 2/9 se bada hai, par kitno se chhota hai woh defined nahi)
Hence, x belongs to (- ∞, 2/9)
(Hinglish: Ek prakar se - ∞ < x < 2/9)
Note: Remember, for < and > we use ( ) brackets & for ≤ and ≥ we use [ ] brackets.
God Bless :)
Answer:
x/5 < (2 - 5x)/20
→ 20x/5 < (2 - 5x) [i just shifted 20 to another side]
→ 4x < 2 - 5x
→ 9x < 2 → x < 2/9
Okay, so x is smaller than 2/9 but how much it is greater to other values isn't defined
Step-by-step explanation: