Question

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Answer 1

Answer:

Electrostatic

Explanation:

★ Numerical Problem 1

no. of electrons = 4 × 10^-18

we know that ;

Q ( charge ) = n ( no. of electrons ) × e ( 1 electron )6

Q = 4 × 10^-18 × 1.6 × 10^-19

Q = 6.4 × 10^-37 Coulumb ( answer )

★ Numerical Problem 2

Electrons in 1 Coulumb charge is 6 × 10^18 electrons.

hope it helps you

Answer 2

Explanation:

1) Q = (no. of electrons) × (charge on electrons)

$</strong><strong>Q</strong><strong> \: = \: 4 \times {10}^{ - 18} \times 1.6 \times {10}^{ - 19} \\ </strong><strong>Q</strong><strong> = 6.4 \times {10}^{ - 37}</strong><strong>C</strong><strong>$

No. of electrons is 1C is 6 × 10^ 18