Question

plzzzz find the value for the attatchment

Answer 1

Answer:

The value is 3.

Step-by-step explanation:

let

$x = \sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{6... \infty } } } }$

$x = \sqrt{6 + x}$

squaring both side,we get

x²= 6 + x

x²- x - 6 = 0

x² - 3x + 2x -6= 0

x(x - 3) + 2 (x - 3) = 0

(x - 3) (x + 2) = 0

x= 3,-2

and, negative value can't be in root. So, The value is 3.

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