Question

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Answer 1

Answer:

sina = p/h = 2pq/p²+q²

so, base (b) = √(h²-p²) = √(p²+q²+2p²q²)-4p²q²

b = √(p²+q²-2p²q²)

b = √(p-q)² = (p-q)

so,

seca = h/b

tana = p/b

putting values we get,

seca-tana = (h-p)/b = (p²+q²-2pq)/(p-q) = (p-q)²/(p-q) = (p-q) (Ans) (None of these)

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Answer 2

NONE OF THESE

Step-by-step explanation:

A/Q

sin alpha=2pq/p^2+q^2

To find:

sec alpha - tan alpha

We know that,

sin alpha= Perpendicular/hypotenuse

Here

Perpendicular=2pq

hypotenuse=p^2+q^2

base=√hypotenuse^2-perpendicular^2

base=√p^4+q^4+2p^2q^2-4p^2q^2

base=√(p-q)^2

base=(p-q)

sec alpha=hypotenuse/base

sec alpha= p^2+q^2/(p-q)

tan alpha= perpendicular/base

tan alpha= 2pq/(p-q)

sec alpha - tan alpha

p^2+q^2/(p-q)-2pq/(p-q)

p^2+q^2-2pq/(p-q)

(p-q)^2/(p-q)

(p-q)^2/(p-q)

(p-q)