Question

plzzzz give me his answer​

Answer 1

Answer :-

Given:-

• Rainfall in City A = $3 \dfrac{3}{5} \: cm$

• Rainfall in City B = $3 \dfrac{5}{8} \: cm$

• Rainfall in City C = $3 \dfrac{4}{7} \: cm$

Now we have to find out the least

rainfall

For it we must find LCM of all

denominators

Denominators :-

5 , 8 , 7

♦ Now by prime factorization

5 = 5 × 1

8 = 2 × 2 × 2

7 = 7 × 1

♦ Then LCM

= 5 × 7 × 8

= 280

♦ Now we will Simplify the fractions

City A >> $3 \dfrac{3}{5} \: cm$ = $\dfrac{18 }{5} \: cm$

City B >> $3 \dfrac{5}{8} \: cm$ = $\dfrac{29}{8} \: cm$

City C >> $3 \dfrac{4}{7} \: cm$ = $\dfrac{25}{7} \: cm$

♦ Now we will find least among them

by making denominators equal

City A >> $\dfrac{18 }{5} \: cm$ = $\dfrac{1008 }{280} \: cm$

City B >> $\dfrac{29}{8} \: cm$ = $\dfrac{1015}{280} \: cm$

City C >> $\dfrac{25}{7} \: cm$ =$\dfrac{1000}{280} \: cm$

♦ So from above we can clearly see that City C received least rainfall

So Answer >> City C