Question

plzzzz give me the ans. of this question guyzzz...

Answer 1

let the no. of moles of (NH₄)₃PO₄ be x.

if we consider 1 mole of the compound, then

12 moles of H atoms are in 1 mole of the compound.

then 3.18 moles are in 1/12 * 3.18=0.265 moles of (NH₄)₃PO₄..

similarly, 1 mole of (NH₄)₃PO₄ contains 4 moles of O atoms

then 0.26 moles contains= 4*0.265 moles

=1.06 moles (3)

hope it helps :)