Physics, asked by Shrutidec20, 1 year ago

plzzzz guys help me with it

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Answered by mahendrachoudhary123
1
vector F12=kq1q2/b^2 i^
magnitude F13=kq1q3/a^2
vector F13=kq1q2/a^2sin@ i^-kq1q3/a^2cos@ j^

here @=theta.
net force on q1=vectorF12+vectorF13
=choice 4 is answer.
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